-4b^2-10b+6=0

Solution for -4b^2-10b+6=0 equation:

-4b^2-10b+6=0

a = -4; b = -10; c = +6;
Δ = b2-4ac
Δ = -102-4·(-4)·6
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-14}{2*-4}=\frac{-4}{-8}
=1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+14}{2*-4}=\frac{24}{-8}
=-3
$